MATH SOLVE

3 months ago

Q:
# I'll give brainliest if you show your answer. Plz answer before thirty minutes.The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.Means and Mean Absolute Deviations of Individual Times of Members of 4*200- meter Relay Swim TeamsTeam A Team BMean 127.9 s 127.4 sMean Absolute Deviation 0.26 s 0.23 sThe difference of the means is found and then compared to each of the mean absolute deviations. Which is true?The difference between the mean times is about equal to the mean absolute deviation of the data sets.The difference between the mean times is about 2 times the mean absolute deviation of the data sets.The difference between the mean times is about 5 times the mean absolute deviation of the data sets.The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Accepted Solution

A:

The difference between the mean times is about 16 times the mean absolute deviation of the data set.

127.9-127.4=0.5

0.26-0.23=0.03

0.5/0.03=16.6666

About 16 times

127.9-127.4=0.5

0.26-0.23=0.03

0.5/0.03=16.6666

About 16 times