Two numbers are such that one number is 42 more that the second number and their average is equal to 40. What is the larger of the two numbers?

Answer: The larger number be 61.Step-by-step explanation:Let the second number be 'x'.Let the first number be 42+xAverage of two numbers = 40According to question,[tex]\dfrac{x+42+x}{2}=40\\\\\dfrac{2x+42}{2}=40\\\\2x+42=80\\\\2x=80-42\\\\2x=38\\\\x=\dfrac{38}{2}\\\\x=19[/tex]So, the larger number of the two numbers i.e the first number is [tex]42+x\\\\=42+19\\\\=61[/tex]Hence, the larger number be 61.